Revert Lacarrete lod file

[nicolasg]

Hi, I'm trying to reverse the .lod of the lacarrete system, but I don't understand the last 2 values.

If i'm not wrong the first one is a int of 4 bytes and the second one is a int of 1 byte





0-1-1

1-1-13

2-2-3

2-2-18

3-2-9

3-2-21

4-2-11

4-2-23

5-2-5

5-2-16

6-3-7

6-3-12

6-3-20

7-3-6

7-3-14

7-3-24

8-4-4

8-4-10

8-4-17

8-4-22

9-4-2

9-4-8

9-4-15

9-4-19

0-1-1

1-1-13

2-2-3

2-2-18

3-2-9

3-2-21

4-2-11

4-2-23

5-2-5

5-2-16

6-3-7

6-3-12

6-3-20

7-3-6

7-3-14

7-3-24

8-4-4

8-4-10

8-4-17

8-4-22

9-4-2

9-4-8

9-4-15

9-4-19

0-1-1

1-1-13

2-2-3

2-2-18

3-2-9

3-2-21

4-2-11

4-2-23

5-2-5

5-2-16

6-3-7

6-3-12

6-3-20

7-3-6

7-3-14

7-3-24

8-4-4

8-4-10

8-4-17

8-4-22

9-4-2

9-4-8

9-4-15

9-4-19



The first value is the iteration of the first loop (for (int k=0; k<LACARETTE_GIFTDATA_TOTAL; ++k) {) the rest are the values that I mentioned at the beginning of the post, but I don't find them logical ?

[WhosUrDaddi]

First Number = The number that is on the board so your number + 1

Second Number = How many times it is on the board

Third Number = At which position on the board it is

[nicolasg]

15 minutes ago, WhosUrDaddi said:




2



First Number = The number that is on the board so your number + 1



Second Number = How many times it is on the board



Third Number = At which position on the board it is




ok, it wasn't that far then, I guessed what could be the third number. But not the second, thx^^. In any case the position of the prizes seems absurd to me, taking into account that the server decide everything with a random xd

#Solved